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Reaction Favorability

Reaction Favorability

2 patterns

Thermodynamic and kinetic factors that determine whether a reaction proceeds. Gibbs free energy, enthalpy, entropy, activation energy, and Le Chatelier's principle. Predicting which direction a reaction will go under given conditions.

Incorrect
Gold(III) chloride
AuCl₃
Delta Hf-118 kJ/mol
Bond typeCovalent/Ionic
StabilityDecomposes above 160°C

Correct
Sodium chloride
NaCl
Delta Hf-411 kJ/mol
Bond typeIonic
Lattice energy787 kJ/mol
Why it's wrong

Gold(III) chloride has a much less negative enthalpy of formation and decomposes at relatively low temperatures. Gold's high ionization energy and reluctance to lose electrons make the formation less favorable.

Why it's correct

NaCl formation is far more thermodynamically favorable (Delta Hf = -411 kJ/mol vs -118 kJ/mol). Sodium readily gives up its single valence electron to chlorine, forming a strong ionic lattice with high lattice energy.

Wikipedia: Standard enthalpy of formation
Incorrect
Tert-butyl bromide (tertiary)
(CH₃)₃CBr
Carbon typeTertiary
Steric hindranceVery high
Relative SN2 rate~0

Correct
Methyl bromide (primary)
CH₃Br
Carbon typePrimary (methyl)
Steric hindranceMinimal
Relative SN2 rate~30
Why it's wrong

Tertiary substrates are essentially unreactive via SN2 because three bulky methyl groups block backside attack by the nucleophile. Instead, tertiary substrates react through the SN1 mechanism, which does not require backside approach.

Why it's correct

SN2 reactions proceed much faster at primary carbons because the nucleophile can easily access the electrophilic carbon from the back side. Methyl and primary substrates have minimal steric hindrance, allowing the concerted mechanism to proceed readily.

Wikipedia: SN2 reaction